contestada

Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form.

x + 1 = 3(y – 5)
x – 5 = 3(y + 1)
y – 5 = 3(x + 1)
y + 1 = 3(x – 5)

Respuesta :

PunIntended

The equation for point-slope form is:

(y - y sub 1) = m * (x - x sub 1)

So, we enter the point we have and the slope we have:

(y - 5) = 3 * (x + 1)

The answer is the third choice.

carlosego

For this case we have that the general equation of the line in point-slope form is given by:

[tex] y-yo = m (x-xo)
[/tex]

Where,

m: slope of the line

(xo, yo): point where the line passes

For this case we have:

[tex] m = 3

(xo, yo) = (-1, 5)
[/tex]

Substituting values:

[tex] y-5 = 3 (x - (- 1))
[/tex]

Rewriting we have:

[tex] y-5 = 3 (x + 1)
[/tex]

Answer:

The equation of the line in point-slope form is:

[tex] y-5 = 3 (x + 1)
[/tex]

option 3

Otras preguntas