For this case, the first thing you should know is that the opposite sides of the parallelogram are the same.
Therefore, we have the following equations:
[tex] 3y-6 = 21
5x + 2 = 17
[/tex]
From equation 1 we have:
[tex] 3y = 21 + 6
3y = 27
[/tex]
[tex] y = \frac{27}{3}
y = 9
[/tex]
From equation 2 we have:
[tex] 5x = 17 - 2
5x = 15
[/tex]
[tex] x = \frac{15}{5}
x = 3
[/tex]
Answer:
the value of the variables are:
[tex] y = 9
x = 3 [/tex]
