Respuesta :

You can factor this by using the grouping method.

[tex] (x^3+3x^2)-(6x+18) [/tex]

[tex] x^2(x+3)-6(x+3) [/tex]

Since both groups have the (x+3), that is one of the factors of the polynomial. What is remaining (the x^2 and -6), is the other factor.

Here are the factors:

[tex] (x^2-6)(x+3) [/tex]

Neither can be simplified further, so this is your answer. Hope this helps!

gmany

[tex]x^3+3x^2-6x-18=x^2(x+3)-6(x+3)=(x+3)(x^2-6)\\\\=(x+3)(x^2-(\sqrt6)^2)=(x+3)(x-\sqrt6)(x+\sqrt6)\\\\Used:\\\\a^2-b^2=(a-b)(a+b)[/tex]

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