[tex] \frac{6q}{20(q + r)} [/tex]
You can simplify this expression by dividing the top and bottom by 2
[tex] \frac{6q}{20(q + r)} [/tex] becomes [tex] \frac{3q}{10(q + r)} [/tex]
[tex] \frac{3q}{10(q + r)} [/tex] is your answer
