we are given
For first 6 hours:
average speed is 44 mi/h
so, we can find distance travelled in first 6 hours
[tex] d_1=44*6mi [/tex]
[tex] d_1=264mi [/tex]
For last 4 hours:
average speed is 50mi/h
so, we can find distance travelled in first 6 hours
[tex] d_2=50*4mi [/tex]
[tex] d_2=200mi [/tex]
now, we can find total distance and total time
[tex] d=d_1+d_2 [/tex]
[tex] d=464mi
[/tex]
total time is 4+6=10hours
now, we can find speed
[tex] speed=\frac{464}{10} [/tex]
[tex] speed=46.4mi/h [/tex]..............Answer
