The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If the energy stored by the spring is 12 joules, what is the approximate weight of the spring in pounds?

For this case we have the following equation:
[tex]w = 0.9* \sqrt{E} [/tex]
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
[tex]w = 0.9* \sqrt{12} [/tex]
Making the corresponding calculation:
[tex]w=3.12[/tex]
Answer:
the approximate weight of the spring in pounds is:
[tex]w=3.12[/tex]

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eudora eudora · Answer 2 · 2019-07-20T23:18:12+02:00

Answer:

3.12 pound.

Step-by-step explanation:

Energy due to weight, w, of the spring = 0.9 × [tex]\sqrt{E}[/tex] will be represented by

[tex]W=mg=0.9\sqrt{E}[/tex]

If energy stored by the spring is 12 joules.

Then weight of the spring will be

m'g = w' = 0.9[tex]\sqrt{12}[/tex]

= 0.9 × 3.46

= 3.12 pounds

The approximate weight of the spring is 3.12 pound.