Respuesta :
1) Altogether ribbons = 10+12=22
Choosing red - 10/22.
2) When red is removed we still have 12 blue ribbons, but altogether now we have 9 red +12 blue = 21 ribbons
Choosing blue - 12/21.
3) Choosing red and then blue - 10/22*12/21 =5/11*12/21 = 60/231
If you need % then, (60/231)*100 = 25.97%.
Choosing red - 10/22.
2) When red is removed we still have 12 blue ribbons, but altogether now we have 9 red +12 blue = 21 ribbons
Choosing blue - 12/21.
3) Choosing red and then blue - 10/22*12/21 =5/11*12/21 = 60/231
If you need % then, (60/231)*100 = 25.97%.
Hello!
There are 22 total ribbons. First of all we have the probability of selecting a red ribbon.
10/22=5/11
Since we took one out without replacing we put the probability out of 21.
12/21
Now we multiply the probabilities.
5/11(12/21)=60/231
I hope this helps!
There are 22 total ribbons. First of all we have the probability of selecting a red ribbon.
10/22=5/11
Since we took one out without replacing we put the probability out of 21.
12/21
Now we multiply the probabilities.
5/11(12/21)=60/231
I hope this helps!