You can find the solutions by graphing y = 4|2x -6| + 3 into [tex] Y_{1}
[/tex] and
y = 19 into [tex] Y_{2} [/tex], and then find the intersections.
The intersections are x = 1 and x = 5.
Now, lets check it! It's always good to check your answers. :)
x = 1, 4|2x - 6| + 3 = 19
4|2(1) - 6| + 3 = 19
4|2 - 6| + 3 = 19
|8 - 24| + 3 = 19
|-16| + 3 = 19
16 + 3 = 19
19 = 19 It works!
4|2(5) - 6| + 3 = 19
4|10 - 6| + 3 = 19
|40 - 24| + 3 = 19
|16| + 3 = 19
16 + 3 = 19
19 = 19
Therefore, x = 1 and x = 5 which is c. :)
