joesph9790
joesph9790
29-06-2018
Mathematics
contestada
solve for x in the equation x2-8x+41=0
Respuesta :
gmany
gmany
03-07-2018
[tex]x^2-8x+41=0\ \ \ \ |-41\\\\x^2-2\cdot x\cdot4=-41\ \ \ \ |+4^2\\\\\underbrace{x^2-2\cdot x\cdot4+4^2}_{(a-b)^2=a^2-2ab+b^2}=-41+4^2\\\\(x-4)^2=-41+16\\\\(x-4)^2=-25 < 0[/tex]
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