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Calculate the mass of hcl required to prepare 2.5 liters of a 0.08 molar solution of hcl. 1 h 1.01 hydrogen 17 cl 35.45 chlorine

a. 3.2 grams

b. 4.5 grams

c. 7.3 grams

d. 11.4 grams

Respuesta :

[tex] \frac{moles}{volume}=C M_{} [/tex]
CM=0.08M , V=2.5 Lit.⇒moles=0.2mol.[tex]0.2molHCl × \frac{35.45gCl+1.01gH}{1mol HCl} =7.292gHCl [/tex]it's the choice c

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