Respuesta :
Distribute 5 to all monomials inside the parenthesis
5(m + 4) = 5m + 20
5m + 20 = 2m + 20
Isolate the m, subtract 2m from both sides, and 20 from both sides
5m (-2m) + 20 (-20) = 2m (-2m) + 20 (-20)
5m - 2m = 20 - 20
Simplify
3m = 0
isolate the m, divide 3 from both sides
3m/3 = 0/3
m = 0/3
m = 0
hope this helps
5(m + 4) = 5m + 20
5m + 20 = 2m + 20
Isolate the m, subtract 2m from both sides, and 20 from both sides
5m (-2m) + 20 (-20) = 2m (-2m) + 20 (-20)
5m - 2m = 20 - 20
Simplify
3m = 0
isolate the m, divide 3 from both sides
3m/3 = 0/3
m = 0/3
m = 0
hope this helps
We can solve this equation by using the distributive property to open up 5(m+4), and then getting m on one side and the constants on the other and then solving for m. Doing this gives us:
5m+20=2m+20 Now we get m on one side
3m=0 Divide each side by 3
m=0 The answer
5m+20=2m+20 Now we get m on one side
3m=0 Divide each side by 3
m=0 The answer