The coordinates of A’B’C’ are:
A'(2,1)
B'(1,2)
C'(3,2)
The vertices of the triangle shaped garden is given by:
A(4,2), B(2,4), C(6,4)
As we know that if a figure is dilated by a fixed scale factor than each of the vertices also get multiplied by the same factor.
i.e. if any figure with a vertex as A(a,b) is dilated by a scale factor k then the coordinated of the dilated figure is: A'(ka,kb)
Here we have: k=0.5
Hence, we get:
A(4,2) → A'(0.5×4,0.5×2)=A'(2,1)
B(2,4) → B'(2×0.5,4×0.5)=B'(1,2)
C(6,4) → C'(6×0.5,4×0.5)=C'(3,2)
Hence, the coordinates of the transformed image is:
A'(2,1)
B'(1,2)
C'(3,2)
