Answer : The equilibrium constant will be - 0.454
Explanation : The reaction is given below;
[tex]COCl_{2} \ \textless \ ----\ \textgreater \ CO + Cl_{2} [/tex]
We need to find Equilibrium constant - [tex] K_{c} [/tex];
[tex] K_{c} [/tex] = [CO] [[tex]Cl_{2} [/tex]] / [tex][COCl_{2} ][/tex]
So, [tex] K_{c} [/tex] = [0.046] X [0.046] / [0.5 - 0.046]
Therefore, [tex] K_{c} [/tex] = 0.454