Respuesta :

MrGumby
The correct answer would be [tex] \frac{-5 +/- \sqrt{13} }{2} [/tex]

In order to solve for this you must first get the equation equal to 0. 

x^2=-5x-3 ----> add 5x to both sides. 
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

[tex] \frac{-b +/- \sqrt{b^{2} - 4ac } }{2a} [/tex]

[tex] \frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)} [/tex]

[tex] \frac{-5 +/- \sqrt{13} }{2} [/tex]

And those would be your two answers.

Answer:

B

x₁ =[tex]\frac{-5-\sqrt{13} }{2}[/tex] , x₂= [tex]\frac{-5 + \sqrt{13} }{2}[/tex]

Step-by-step explanation:

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