Respuesta :
Answer:
[tex]\frac{36+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{9}[/tex]
Explanation:
1) Expression given:
[tex] \frac{9+ \sqrt{2} }{4- \sqrt{7} } [/tex]
2) Rationalize by multiplying and dividing by the conjugate of the denominator
[tex] \frac{(9+ \sqrt{2} )}{(4- \sqrt{7} )} \frac{(4 + \sqrt{7} )}{(4+ \sqrt{7} )} [/tex]
3) Due the operations
[tex] \frac{9(4)+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{4^2-7} =[/tex]
[tex]\frac{36+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{9}[/tex]
[tex]\frac{36+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{9}[/tex]
Explanation:
1) Expression given:
[tex] \frac{9+ \sqrt{2} }{4- \sqrt{7} } [/tex]
2) Rationalize by multiplying and dividing by the conjugate of the denominator
[tex] \frac{(9+ \sqrt{2} )}{(4- \sqrt{7} )} \frac{(4 + \sqrt{7} )}{(4+ \sqrt{7} )} [/tex]
3) Due the operations
[tex] \frac{9(4)+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{4^2-7} =[/tex]
[tex]\frac{36+9 \sqrt{7} +4 \sqrt{2} + \sqrt{14} }{9}[/tex]
Answer:
C on EDGE
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