Respuesta :
B. S⁰(s) + 2H⁺ + 2e⁻ –--> H2S⁰(g)
by mass: 1 S and 2 H ----> 2 H and 1S True.
by charge : 0 +(2*(+1)) + 2*(-1) = 0, 0+2-2=0, 0 = 0 True.
by mass: 1 S and 2 H ----> 2 H and 1S True.
by charge : 0 +(2*(+1)) + 2*(-1) = 0, 0+2-2=0, 0 = 0 True.
The following equation(option B) is balanced for charge and mass
A. S(s) + 2H+ → H2S(g) + 2e–
B. S(s) + 2H+ + 2e– → H2S(g)
C. S(s) + 2e- →H2S(g)
D. S(s) + 2H+→ H2S(g)
S(s) + 2H+ + 2e– → H2S(g)
here S is one on either sides
H is two on either sides, hence mass is balanced.
And charge is also balanced,
as 2H+ has +2 charge
and 2e- has -2 charge,thus
total charge on left side is +2-2 = 0
and charge on right side is also zero here or no charge on either sides.