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What was the equation of the graph below before it was shifted to the right 1 unit? (equation was g(x)=(x-1.5)^3-(x-1.5))
a. g(x)=(x-.5)^3
b. g(x)=(x-2)^3-(x-2)
c. g(x)=(x)^3
d. g(x)=(x-0.5)^3-(x-0.5)

ps: answer is worth 2 points on apex

Respuesta :

frika
If graph of the function y=f(x) was shifted to the  right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function [tex]g(x)=(x-1.5)^3-(x-1.5)[/tex] that is obtained by shifting to the right 1 unit, then the initial function was

[tex]g(x+1)=(x+1-1.5)^3-(x+1-1.5), \\ g(x+1)=(x-0.5)^3-(x-0.5)[/tex].
Answer: Correct choice is D.
jinchengzhaoliii

Answer:

d

Step-by-step explanation:

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