Respuesta :

limacharliesierra
Circle equation:
[tex](x - xo)^{2} + (y - yo)^{2} = {r}^{2} [/tex]

Center (0, 3)
Xo = 0
Yo = 3

Radius: 7
r = 7

So:

[tex](x - 0)^{2} + (y - 3)^{2} = {7}^{2} [/tex]
[tex]{x}^{2} + (y - 3)^{2} = 49[/tex]

Answer: x^2 + (y - 3)^2 = 49
gmany
[tex]\text{The standard form of the circle:}\\\\(x-h)^2+(y-k)^2=r^2\\\\\text{h and k are the x and y coordinates of the center}\\\\\text{We have:}\\\\\text{the center}\ (0;\ 3)\to h=0;\ k=3\\\\\text{the radius}\ r=7\\\\\text{substitute:}\\\\(x-0)^2+(y-3)^2=7^2\\\\x^2+(y-3)^2=49[/tex]