You have to multiply each term by what it's missing for the denominators to both be the same. The first term has x+3 but is missing x-5 so multiply top and bottom by x-5 and then distribute the numerator to -2x + 10. Do the same for the other term that is missing the x+3 and distribute to get -(4x+12). Distribute the negative in then simplify to get [tex] \frac{-6x-2}{(x+3)(x-5)} [/tex] or simplify even further to get [tex] \frac{-2(3x+1)}{(x+3)(x-5)} [/tex]
