The ice cream cone consists of a semi-circle with a diameter of 10 cm and a triangle with a base of 10 cm and height of 12 cm.
The area of a semi-circle is half the area of a full circle, so we can find it by using:
[tex]A= \frac{1}{2} \pi r^2[/tex]
If the diameter of the circle is 10 cm, then the radius is 5 cm. Plug in the known values:
[tex]A= \frac{1}{2} \pi (5)^2[/tex]
[tex]A = 12.5 \pi[/tex] or about 39.25
The area of a triangle is:
[tex]A = \frac{1}{2} bh[/tex]
So we can plug in the known values to find the area to be:
[tex]A= \frac{1}{2} (10)(12)=60[/tex]
When we add the areas of the two sections together, we get an exact answer of:
(60 + 12.5pi) cm^2
or about 99.25 cm^2
