Hi there! The answer is {-2, 2}
Let's solve this problem step by step!
[tex]7 {q}^{2} - 28 = 0[/tex]
First add 28 to both sides.
[tex]7 {q}^{2} = 28[/tex]
Now divide both sides by 7.
[tex] {q}^{2} = 4[/tex]
Take the root of both sides, and the negative root of 4.
[tex]q = \sqrt{4} \: \: or \: \: q = - \sqrt{4} \\ q = 2 \: \: \: \: \: \: or \: \: q = - 2[/tex]
Therefore the solution set to this equation is {-2, 2}
~ Hope this helps you!
