Respuesta :
You have put both in slope intercept form;;;;
y=2/3x-17 (already in slope-intercept form)
4x-6y=-6 (standard form)
For this, add 6y to both sides, and add 6 to both sides giving you...
6y=4x-6
Divide by 6 on both sides...
y=2/3x-1
Since both equations have the same slope, the graphs will be parallel.
y=2/3x-17 (already in slope-intercept form)
4x-6y=-6 (standard form)
For this, add 6y to both sides, and add 6 to both sides giving you...
6y=4x-6
Divide by 6 on both sides...
y=2/3x-1
Since both equations have the same slope, the graphs will be parallel.
To determine whether two lines are parallel, we need to look at the slopes of those lines. If they are the same, they are parallel.
We have two lines:
[tex]y= \frac{2}{3}x-17 [/tex]
[tex]4x-6y=-6[/tex]
In order to compare the slopes, let's rearrange the second equation to look like the first:
[tex]4x-6y=-6[/tex]
[tex]-6y=-4x-6[/tex]
[tex]y= \frac{-4}{-6}x+ \frac{-6}{-6} [/tex]
[tex]y= \frac{2}{3}x+1 [/tex]
So then let's compare these two equations again.
[tex]y= \frac{2}{3}x-17 [/tex]
[tex]y= \frac{2}{3}x+1 [/tex]
In slope-intercept form, y = mx +b, m is equal to the slope. In this case, both lines have the same slope, and therefore, they are parallel.
We have two lines:
[tex]y= \frac{2}{3}x-17 [/tex]
[tex]4x-6y=-6[/tex]
In order to compare the slopes, let's rearrange the second equation to look like the first:
[tex]4x-6y=-6[/tex]
[tex]-6y=-4x-6[/tex]
[tex]y= \frac{-4}{-6}x+ \frac{-6}{-6} [/tex]
[tex]y= \frac{2}{3}x+1 [/tex]
So then let's compare these two equations again.
[tex]y= \frac{2}{3}x-17 [/tex]
[tex]y= \frac{2}{3}x+1 [/tex]
In slope-intercept form, y = mx +b, m is equal to the slope. In this case, both lines have the same slope, and therefore, they are parallel.