Respuesta :
Answer: The number of [tex]OH^-[/tex] ions present in given amount of calcium hydroxide is [tex]3.6132\times 10^{24}[/tex]
Explanation:
Equation representing ionization of calcium hydroxide follows:
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]
[tex]Ca(OH)_2[/tex] is a base which releases 2 hydroxide ions [tex](OH^-)[/tex]
According to mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules of ions.
So, 3 moles of [tex]Ca(OH)_2[/tex] will contain [tex]3\times 2\times 6.022\times 10^{23}=36.132\times 10^{23}=3.6132\times 10^{24}[/tex] number of [tex]OH^-[/tex] ions
Hence, the number of [tex]OH^-[/tex] ions present in given amount of calcium hydroxide is [tex]3.6132\times 10^{24}[/tex]
3 moles of Ca(OH)₂ will release [tex]3.61*10^{24} moles[/tex] [tex]OH^{-}[/tex] ions.
Firstly, write the ionization equation for calcium hydroxide.
[tex]Ca(OH)_2[/tex] → [tex]Ca^{2+}+2OH^{-}[/tex]
Calcium hydroxide releases two hydroxide ions and one calcium ion.
Mole concept:
- One mole of a substance is equal to 6.022 × 10²³ units of that substance
- The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant.
Therefore, 3 moles of Ca(OH)₂ will contain
[tex]3*6.022*10^{23}=18.066*10^{23}moles[/tex]
Now, 1 mole of Ca(OH)₂ release 2 moles of [tex]OH^{-}[/tex] ions.
So, 3 moles of Ca(OH)₂ will release
[tex]\frac{2}{1} *18.066*10*{23}=36.132*10^{23}=3.61*10^{24} moles[/tex]
3 moles of Ca(OH)₂ will release [tex]3.61*10^{24} moles[/tex] [tex]OH^{-}[/tex] ions.
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