2AB₂(g)⇔2AB(g)+B₂(g)
Degree of dissociation of AB2 is x. What will be equation for x in terms of Kp and equilibrium pressure P ?

A. Kₚ =x³/(2+x)(1−x)²×P
B. x=√P/2Kₚ
C. x=√2Kₚ/P
D. Kₚ=x²/(2+x)(1−x)×P