Calculate the work (kJ) done during a reaction in which the internal volume expands from 19 L to 48 L againts an outside pressure of 2.5 atm. W=-PdeltaV and atm.L= 101.235J
A) -7.3 kJ
B) 17 kJ
C) 7.3 kJ
D) -17 kJ
E) 0 kJ; No work is done