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4 NH3(g) + 5 O2(g) -> 4 NO(g) + 6 H2O(g)If 82.0 moles of NH3 react with sufficient oxygen, how many moles of water should form?1. 61.1 moles2. 12.3 moles 3. 8.25 moles4. 22 moles 5. 123moles

4 NH3g 5 O2g gt 4 NOg 6 H2OgIf 820 moles of NH3 react with sufficient oxygen how many moles of water should form1 611 moles2 123 moles 3 825 moles4 22 moles 5 1 class=

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